Question

# An oleum sample is labelled as $$118\%$$. The mass of $$H_{2}SO_{4}$$ in $$100$$ g oleum sample is:

A
20 g
B
25 g
C
28 g
D
30 g

Solution

## The correct option is D $$20$$ gAs we know,Percent labeling of oleum $$=$$ $$100$$ $$+$$ Total mass of water required to completely convert oleum into $$H_2SO_4$$. So, we need $$18$$ g of water for the reaction $$SO_3 + H_2O \rightarrow H_2SO_4$$, 1 mole of water is required, which in turn means that 1 mole of $$SO_3$$ is present. Therefore, in a 100 g sample, 80 g is $$SO_3$$.Hence, the mass of $$H_2SO_4 =$$ $$20$$ g. Chemistry

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