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Question

An oleum sample is labelled as $$118\%$$. The mass of $$H_{2}SO_{4}$$ in $$100$$ g oleum sample is:


A
20 g
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B
25 g
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C
28 g
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D
30 g
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Solution

The correct option is D $$20$$ g
As we know,

Percent labeling of oleum $$=$$ $$100$$ $$+$$ Total mass of water required to completely convert oleum into $$H_2SO_4$$.
 
So, we need $$18$$ g of water for the reaction $$SO_3 + H_2O \rightarrow H_2SO_4$$, 

1 mole of water is required, which in turn means that 1 mole of $$SO_3$$ is present. Therefore, in a 100 g sample, 80 g is $$SO_3$$.

Hence, the mass of $$H_2SO_4 = $$ $$20$$ g. 

Chemistry

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