Question

An open container contains a certain gas and is heated from $27{}^{\circ }C$ to $127{}^{\circ }C$. What mole percentage of the gas escapes from the container?

• A. 40%
• B. 25%
• C. 33%
• D. 50%

Answer 1

The correct option is B 25%

We know, $PV=nRT$
Since we are heating the same container and in open air, the pressure and the volume are same in both cases. Thus, we can equate,
$n_1{T}_1=n_2{T}_2$
$n_1\times 300=n_2\times 400$
$n_2=\frac{3}{4}{n}_1$
% mole escaped = $\frac{n_1-\frac{3}{4}{n}_1}{n_1}\times 100=25\%$