An open lift is moving upwards with velocity 10 m/s. It has an upward acceleration of 2 m/s2. A ball is projected upwards with velocity 20 m/s relative to ground. Find the time when ball again meets the lift.
The correct option is D53s At the time when ball again meets the lift, sL=sB ∴10t+12×2×t2=20t−12×10t2 Solving this equation, we get ∴ Ball will again meet the lift after 53s.