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Question

An open lift is moving upwards with velocity 10m/s. It has an upward acceleration of 2m/s2. A ball is projected upwards with upwards with velocity 20m/s relative to the ground. Find the time when the ball again meets the lift.

A
53s
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B
43s
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C
34s
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D
14s
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Solution

The correct option is A 53s
Let the time of Height of the ball be t. Then. with respect to the lift.
VB/L=VBVL=2010=10 m/s
aB/L=aBaL=(10)(2)=12 m/s2
To find t, applying second eqn to motion
h=u(t)+at2
o=(10)(t)+(12)t22
bt2=10t
t=5/33
Option A is correct.

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