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Question

An organic compound 'A' on treatment with NH3 gives 'B', which on heating gives 'C'. 'C', when treated with Br2 in the presence of KOH, produces ethylamine. Compound 'A' is:

A
CH3CH2COOH
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B
CH3COOH
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C
CH3CH2CH2COOH
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D
CH3CH(CH3)COOH
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Solution

The correct option is A CH3CH2COOH
When propanoic acid is reacted with liq.ammonia it gives 1-amino propanone and water as a byproduct
1-amino propanone is reacted with bromine in presence of potassium hydroxide, Hofmann bromamide reaction takes place which gives ethylamine as a product.
Thus Propanoic acid (CH3CH2COOH) is the correct answer.

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