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Question

An organic compound contains carbon, hydrogen and oxygen. Its elemental analysis gave C, 38.71% and H, 9.67%. The empirical formula of the compound would be?

A
CH4O
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B
CH3O
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C
CH2O
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D
CHO
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Solution

The correct option is B CH3O
The empirical formula is to be calculated as:
Element % Composition Atomic MassMole Ratio Simple Ratio
C 38.71 12 38.7112=3.22 3.223.22=1
H 9.67 1 9.671=9.67 9.673.22=3
O 100-(38.71+9.67) =51.62 16 51.6216=3.22 3.223.22=1
Hence the empirical formula of the compound is CH3O

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