An organic liquid of the composition $C_{4} H_{8} O_{2}$ yields a sodium salt of an acid $C_{3} H_{6} O_{2}$ and methanol on boiling with $N a O H$ solution. The given liquid is:

C H_{3} C O O C_{2} H_{5}

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C H_{3} C H_{2} C O O C H_{3} 5

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H C O O C_{3} H_{7}

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C H_{3} C H_{2} C H_{2} C O O H

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Solution

The correct option is A $C H_{3} C O O C_{2} H_{5}$
The reaction is as follows :
$C H_{3} C O O C_{2} H_{5} + N a O H \to C H_{3} C H_{2} C O O N a + C H_{3} O H$

$1$ Degree of Unsaturation with 2 $O$ atoms and on hydrolysis gives salt of an acid and ${C H}_{3} O H$ . So, compound is methyl acetate ie., $({C H}_{3} {C H}_{2} C O O M e)$ Hence option (A) is correct.

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