Question

# An oxide of sulphur contains 50 % S. What will be its emprical formula ? (1) SO (2) SO2 (3) SO3 (4) S2O3

Solution

## (2) Percentage of S = 50 So, Percentage of O = 50 Therefore, 50 g of S and O are present. Moles of S = 50/32 = 1.5625 Moles of O =50/16 = 3.125  Divide both by smaller one (ie 1.5625) S =  1.5625/1.5625  = 1 O =  3.125/1.5625  = 2 So, empirical formula = SO2  ​​​​ So the Answer is (2)

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