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Question

An oxide of sulphur contains 50 % S. What will be its emprical formula ?
(1) SO
(2) SO2
(3) SO3
(4) S2O3


Solution

(2)
Percentage of S = 50
So, Percentage of O = 50
Therefore, 50 g of S and O are present.
Moles of S = 50/32 = 1.5625
Moles of O =50/16 = 3.125
 Divide both by smaller one (ie 1.5625)
S =  1.5625/1.5625  = 1
O =  3.125/1.5625  = 2
So, empirical formula = SO2
 ​​​​
So the Answer is (2)

 

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