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Question

An particle is situated in an electric field of 106 N/C. The force exerted on it is


A
6.4×103N
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B
3.2×1013N
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C
32×1013N
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D
64×1013N
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Solution

The correct option is B 3.2×1013N
F=Eq
=106×2×1.6×1019
=3.2×1013N

Physics

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