Question

An $U-$tube is partially filled with water. An immiscible oil having density $0.8g/cc$, is poured into one side until water rises by $25cm$, on the other side. The level of oil will stand higher than level of water by ?

• A. $125cm$
• B. $75cm$
• C. $22.5cm$
• D. $12.5cm$

Answer 1

The correct option is D $12.5cm$

$\text{it raise in height of water}=25$

$\text{then diff b/w heights of water}=50$

$\text{Since pressure of liq.s water}$

$\text{is same.}$

${\rho }_{w}g\left(50\right)={\rho }_{0}g\times h$

$1\times 50=0.8\times 17$

$h=62.5cm$

$So\Delta h=62.5-50$

$=12.5cm$

Answer:-$\left(D\right)$