An unbiased cubic die marked with 1,2,2,3,3,3 is rolled 3 times. The probability of getting a total score of 4 or 6 is
A
16216
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B
50216
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C
60216
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D
none of these
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Solution
The correct option is B50216 P(getting1)=16P(getting2)=26=13P(getting3)=36=12 When the die is thrown 3 times a total of 4 or 6 can be obtained from following combinations (1,1,2),(2,2,2),(1,2,3). Let the event of getting 4 or 6 be called E. Then P(E)=(3!2!)P(1)P(1)P(2)+P(2)P(2)P(2)+(3!)P(1)P(2)P(3)=3×16×16×13+13×13×13+(3!)×16×13×12=25108=50216