Question

# An unequal side of an isosceles triangle is 24 cm and its area is 60cm 2 find the perimeter of isosceles triangle .

Solution

## Area of an isosceles triangle=1/2×base×height Here, let the unequal side be the base , SoBase=24cm Area of isosceles triangle= 1/2×24×height=60 So,12h= 60 Hence,h=60/12=5cm Now height=5cm base=24cm So,hypotenuse=? We know by Pythagoras theorem that (AB)²+(BC)²= (AC)² Here a=24/2=12cm (As base is divided into two parts by the altitude) b=5cm So, (hypotenuse)²= (12)²+(5)²=169cm So,side=hypotenuse=√169=13cm So, Perimeter=24cm+13cm+13cm=50cm Hope this helps :)

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