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Question

An unknown voltage source Eu (negligible internal resistance) is connected to a potentiometer circuit as shown in the following figure. If the galvanometer current is 10 μA with the direction as indicated, then value of Eu is

A
0.9910 V
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B
0.9991 V
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C
1.0012 V
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D
1.0048 V
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Solution

The correct option is D 1.0048 V

Ig=10 μA=105 A

writing KVL in Loop 1, we get

1.6100 I500 I1000(I+Ig)=0

1.61000 Ig=1600 I

1.61000×105=1600 I

I=1.60.011600=9.9375×104 A

Now in loop 2,

Eu=105×100+1000×105+1000×9.9375×104

=1100×105+0.99375

= 0.011 + 0.99375

= 1.00475 = 1.0048 V

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