Question

# An urn contains 5 different red and 6 different green balls. In how many ways can 6 balls be selected so that there are at least two balls of each colour?

A
425
B
245
C
125
D
625

Solution

## The correct option is A 425Total number of red balls = 5 Total number of green balls = 6 Possbile combination are: RedGreen243342 Required number of selections = (5C2×6C4) + (5C3×6C3) + (5C4×6C2) = 425

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