Question

An X-Ray tube emits X-Rays of wavelength $0.1A^o$ under the application of a potential difference of

• A. 12.4 KV
• B. 24.8 KV
• C. 124 KV
• D. 200 KV

Answer 1

The correct option is C 124 KV

$\lambda =0.1A^{\circ }=0.01nm$
$energy=\frac{hc}{\lambda }$
$=\frac{1240eV-nm}{0.01nm}(hc=1240eV-nm)$
$=124000eV$

$energy=p.d\times e$
$124000eV=p.d\times e$
$124000V=p.d.$
$orp.d=124KV.$

So, the answer is option (C).