Question

Angles opposite to the equal sides of a triangle are equal.

• A. True
• B. False
• C. Incomplete information
• D. None

Answer 1

The correct option is A True

Consider $△ABC$, $\angle B=\angle C$
Construction: Draw a median AD on BC.

Hence, $BD=DC$
Now, In $△ABD$ and $△ACD$
$\angle ADB=\angle ADC$ .... Common angle
$AD=AD$ ..... (Common)
$BD=DC$
Thus, $△ABD\cong △ACD$ .... (SAS rule)
Thus, $\angle B=\angle C$ .... (By CPCT)