Anil and Sunil can complete a job in 15 days and 20 days respectively. Both of them started it together. Anil left 6 days before the work was completed. Find the time taken (in days) to complete the work.

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Solution

The correct option is C 12
Let total work is LCM of (15, 20) = 60

Work done by Anil in a day = 4 units

Work done by Sunil in a day = 3 units

Anil worked for (t – 6) days and Sunil worked for t days.

4(t – 6) + 3t = 60

t = 12; Option (c).

2nd method:- During last 6 days Sunil alone will work i.e $30 %$ of work will be done by Sunil alone. Remaining $70 %$ of work will be done together. In one day both will do $(\frac{100}{15}) + (\frac{100}{20}) = 11.67 %$ , then $70 %$ will complete in 6 days. Total 6+6= 12 days.Option (c).

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