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Question

Answer this question, based on the information given below.
If a,bϵR,a,b>0, then ab14(a+b)2
If a,b>0, a+b=1, then find the least value of (1+1a)(1+1b)

A
3
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B
6
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C
9
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D
12
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Solution

The correct option is D 9
(1+1a)(1+1b)
=(a+1)(b+1)ab
=ab+a+b+1ab
=1+a+b+1ab
=1+2ab ..... (a+b=1)
Now ab14(a+b)2
Therefore
ab14(1)2
ab14 ...(ii)
Hence, the maximum value of ab=14
Substituting in (i), we get
(1+1a)(1+1b)
=1+2ab
1+21/4 =1+8 =9
Hence, the answer is C.

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