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Question

Aqueous solution of 0.004 M Na2SO4 and 0.01 M glucose are isotonic. The degree of dissociation of Na2SO4 is

A
25%
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B
60%
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C
75%
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D
85%
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Solution

The correct option is C 75%
Na2SO42Na++SO24
0.004(1α)0.008α0.004α
Now
0.004(1α)+0.008α+0.004α=0.01
0.008α=0.010.004
0.008α=0.006
α=68=0.75
Percentage dissociation=75%

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