Aqueous solution of 0.004 M $N a_{2} S O_{4}$ and 0.01 M glucose are isotonic. The degree of dissociation of $N a_{2} S O_{4}$ is:

25

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60

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75

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85

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Solution

The correct option is C $75$ %
The degree of dissociation of $N a S O_{4}$ is 75 %

For two solutions to be isotonic

$π_{N a_{2} S O_{4}} = π_{g l u c o s e}$

$C_{1} R T (1 + 2 α) = C_{2} R T$

$0.004 \times (1 + 2 α) = 0.01$

$∴ α = 0.75$ or 75%

Hence, the correct option is $C$

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