The correct option is C (7y 3)(5y+4) Given Area=35y^2+13y 12 nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; ...

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Area of Square

Area:35y2+13y...

Question

$A r e a : 35 y^{2} + 13 y - 12$

(7 y + 3) (5 y + 4)

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(7 y - 3) (5 y - 4)

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(7 y - 3) (5 y + 4)

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(7 y + 3) (5 y - 4)

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Solution

The correct option is C $(7 y - 3) (5 y + 4)$
Given $A r e a = 35 y^{2} + 13 y - 12$
$= 35 y^{2} + 28 y - 15 y - 12$
$= 7 y (5 y + 4) - 3 (5 y + 4)$
$= (7 y - 3) (5 y + 4)$
Therefore, the possible length and breadth are 7y-3 units and 5y+4 units.

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35 y^{2} + 13 y - 12

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