Question

# Area of a rectangle is 51.2 dm square and the sides are in the ratio 5:4 . Find its perimeter

Solution

## Given area of rectangle = 51.2 dm² Sides are in the ratio 5:4 Let x be the common factor Than length = 5x dm Breadth = 4x  dm  Area of rectange = Length * Breadth   51.2 dm² =  5x * 4x dm² 51.2 = 20 x² 2.56 =  x²  x = √2.56 So x = 1.6  Length = 5*x = 8 dm Breadth = 4*x = 4*1.6 = 6.4 dm Perimeter of rectangle = 2*(Length + Breadth ) Perimeter  = 2*(8+6.4) dm  Perimeter  = 2*14.4 = 28.8 dm Answer : 28.8 dm  Mathematics

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