Arrange Cl, F, $F^{-}, C l^{-}$ in increasing order of ionisation potential.

F^{-} < C l^{-} < C l < F

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C l^{-} < F^{-} < F < C l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C l^{-} < F < F^{-} < C l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

F^{-} < C l^{-} < F < C l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $F^{-} < C l^{-} < C l < F$
Fluorine has its valence electrons in 2p orbital while chlorine has 3p so there is more atomic force of attraction in fluorine than chlorine, therefore, the ionisation potential of fluorine is more than chlorine.

Hence, the correct option is $A$

Suggest Corrections

Similar questions

Arrange F, Cl, O, and N in the decreasing order of electronegativity.

I^{-}, B r^{-}, C l^{-}, F^{-}

F^{-}, N a^{+}, S^{2 -}, C l^{-}

K^{+}

Considering the elements F, Cl, O and N, the correct order of their chemical reactivity in terms of oxidizing property is:

(a) F > Cl > O > N (b) F > O > Cl > N

Join BYJU'S Learning Program