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Byju's Answer
Standard VI
Mathematics
Coefficient
Arrange horiz...
Question
Arrange horizontally and add the given expression.
(1) 12c, 7c
(2) bc
2
, 11bc
2
(3) –xyz, 2xyz
(4) –6a
2
b
2
, –4a
2
b
2
(5) 10p
2
q, –qp
2
(6) a
3
, –14a
3
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Solution
(1) We can arrange the like terms as:
12
c
+ 7
c
= (12 + 7)
c
= 19
c
(2) We can arrange the like terms as:
bc
2
+ 11
bc
2
= (1 + 11)
bc
2
= 12
bc
2
(3) We can arrange the like terms as:
–
xyz
+ 2
xyz
= (–1 + 2)
xyz
= (1)
xyz
=
xyz
(4) We can arrange the like terms as:
–6
a
2
b
2
+ (–4
a
2
b
2
)
= (–6 –4)
a
2
b
2
= –10
a
2
b
2
(5) We can arrange the like terms as:
10
p
2
q
+ (–
qp
2
)
= 10
p
2
q
+ (–
p
2
q
)
= (10 – 1)
p
2
q
= 9
p
2
q
(6) We can arrange the like terms as:
a
3
+ (–14
a
3
)
= (1 – 14)
a
3
= –13
a
3
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Similar questions
Q.
Arrange the given expression vertically and add them.
(1) 11x, 6x, –2x
(2) –y
2
, 13y
2
, –5y
2
(3) 4a
2
bc, –9bca
2
, 14cba
2
(4)
1
2
a
x
2
,
3
2
a
x
2
,
-
2
a
x
2
Q.
Simplify the expression:
9
14
a
3
÷
12
21
a
3
=
Q.
The expression
a
3
−
1
a
3
equals
Q.
Add the following expressions:
(i)
x
3
-
2
x
2
y
+
3
x
y
2
-
y
3
,
2
x
3
-
5
x
y
2
+
3
x
2
y
-
4
y
3
(ii)
a
4
-
2
a
3
b
+
3
a
b
3
+
4
a
2
b
2
+
3
b
4
,
-
2
a
4
-
5
a
b
3
+
7
a
3
b
-
6
a
2
b
2
+
b
4
Q.
Simplify the expression
(
1
+
a
)
3
, using the suitable property.
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