Question

Arrange in the increasing order of oxidation state to nitrogen for following nitrogen oxides $N_{2}O,N{O}_2,NO,N_2{O}_3$

• A. $NO<N_{2}O<N{O}_2<N_2{O}_3$
• B. $N_{2}O<N_2{O}_3<N{O}_2<NO$
• C. $N_{2}O<NO<N_2{O}_3<N{O}_2$
• D. $N{O}_2<N_2{O}_3<NO<N_{2}O$

Answer 1

Answer: (C)

$N_{2}O<NO<N_2{O}_3<N{O}_2$

Solution:-

Nitrogen	Ox.state of nitrogen
$N_{2}O$	$+1$
$NO$	$+2$
$N_2{O}_3$	$+3$
$N{O}_2$	$+4$

Thus the correct increasing order is

$N_{2}O<NO<N_2{O}_3<N{O}_2<N_2{O}_5$