Arrange the alkyl in decreasing order of their mass.

C H_{3} C l > H_{2} O > C H_{3} B r

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C H_{3} C l > C H_{3} B r > H_{2} O

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C H_{3} B r > C H_{3} C l > H_{2} O

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H_{2} O > C H_{3} C l > C H_{3} B r

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Solution

The correct option is C $C H_{3} B r > C H_{3} C l > H_{2} O$
$C H_{3} B r$ Atomic mass $\Rightarrow$ $12 + 3 + 80 = 95$
$C H_{3} C l$ Atomic mass $\Rightarrow$ $12 + 3 + 35.5 = 50.5$
$H_{2} O$ Atomic mass $\Rightarrow$ $16 + 2 = 18$
According to given Atomic masses of compounds the decreasing order is $C H_{3} B r > C H_{3} C l > H_{2} O$ .

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