Arrange the elements S, N, Be, Mg and Al in the increasing order of their atomic size:

N < Be < Al < Mg < S

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Be < N < Al < S < Mg

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N < S < Be < Al < Mg

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N < Be < S < Al < Mg

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Solution

The correct option is D N < Be < S < Al < Mg
The atomic size of elements in second period is less than that of third period. Also atomic size decreases towards right in a period. Thus correct order is $\to N < B e < S < A l < M g$

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Question 17
Arrange the following elements in the order of their decreasing metallic character
Na, Si, Cl, Mg, Al

(a) Cl > Si >Al > Mg >Na
(b) Na >Mg >Al >Si > Cl
(c) Na > Al > Mg > Cl > Si
(d) Al > Na> Si > Ca> Mg

Considering the elements B, Al, Mg, and K, the correct order of their metallic character is:
(a) B > Al > Mg > K
(b) Al > Mg > B > K
(c) Mg > Al > K > B
(d) K > Mg > Al > B

Q. Considering the elements

B, A l, M g

and

K

, the correct order of their metallic character is:

Q. In the modern periodic table, arrange the third-row elements

N a, M g, A l

and

S i

in the increasing order of their atomic size.

The first ionistation enthalpies of Na, Mg, Al, and Si are in the order
(a) Na< Mg > Al < Si (b) Na> Mg > Al > Si
(c) Na< Mg< Al< Si (d) Na> Mg> Al < Si

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Arrange the elements S, N, Be, Mg and Al in the increasing order of their atomic size:

The correct option is D N < Be < S < Al < MgThe atomic size of elements in second period is less than that of third period. Also atomic size decreases towards right in a period. Thus correct order is →N<Be<S<Al<Mg

The correct option is D N < Be < S < Al < Mg
The atomic size of elements in second period is less than that of third period. Also atomic size decreases towards right in a period. Thus correct order is $\to N < B e < S < A l < M g$