Question 43

Arrange the following bonds in order of increasing ionic character giving reason.

N - H, F - H, C - H and O - H

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Solution

Greater is the electronegativity difference between the two bonded atoms, greater is the ionic character.

Therefore, increasing order of ionic character of the given bonds is as follows

$\begin{matrix} Bond & N - H & F - H & C - H & O - H Electronegativity & (3.0 - 2.1) = 0.9 & (4.0 - 2.1) = 1.9 & (2.5 - 2.1) = 0.4 & (3.5 - 2.1) = 1.4 d i f f e r e n c e \end{matrix}$

Therefore, increasing order of ionic character of the given bonds is as follows

$C - H < N - H < O - H < F - H$

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