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Question

Arrange the following compounds in increasing order of their boiling points.

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A
(b)<(a)<(c)
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B
(a)<(b)<(c)
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C
(c)<(a)<(b)
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D
(c)<(b)<(a)
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Solution

The correct option is D $$(c) < (a) < (b)$$
The increasing order of the boiling points is $$(c) < (a) < (b)$$. 

As the branching of alkyl halide increases, the boiling point decreases.

Thus, the boiling point of tert butyl bromide is lowest and the boiling point of n butyl bromide is highest.

Option C is correct.

Chemistry

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