Arrange the following equations based on the ascending order of sum of their roots.(Top to bottom direction)

x^{2} - 6 x + 8 = 0

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x^{2} - 4 x + 4 = 0

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x^{2} - 8 x + 16 = 0

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x^{2} - 2 x + 1 = 0

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Solution

General form of quadratic equation in terms of sum of zeros is given by :

$[(x^{2} - (s u m o f r o o t s) x + (p r o d u c t o f r o o t s)] = 0$

Let's find the sum of roots of the given equations.

1. $x^{2} - 6 x + 8 = 0$

On comparing this equation with the general form, we have

Sum of roots = 6

2. $x^{2} - 4 x + 4 = 0$

On comparing this equation with the general form, we have

Sum of roots = 4

3. $x^{2} - 8 x + 16 = 0$

On comparing this equation with the general form, we have

Sum of roots = 8

4. $x^{2} - 2 x + 1 = 0$

On comparing this equation with the general form, we have

Sum of roots = 2

Suggest Corrections

Similar questions

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\frac{x^{2} - 5 x + 12}{5 x - 12} = \frac{x^{2} - x - 4}{x + 4}

${lim}_{x \to 0} \frac{x^{2} + 1 - c o s x}{x s i n x}$

x^{2} + 6 x - 4 = 0 x^{2} + \frac{1}{x^{2}} = 5

Solve the following system of inequations

x2 + x + 8 less than 0

x2 + 6x + 5 greater than 0

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