Arrange the following free radicals in order of decreasing stability :
Methyl $(I)$ , Vinyl $(I I)$ , Allyl $(I I I)$ , Benzyl $(I V)$

I > I I > I I I > I V

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I I I > I I > I > I V

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I I > I > I V > I I I

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I V > I I I > I > I I

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Solution

The correct option is D $I V > I I I > I > I I$ .
Order of stability of given compounds:
$B e n z y l (C_{6} H_{5} -) > A l l y l (C H_{2} = C H_{2} C H_{2} -) > M e t h y l (C H_{3} -) > V i n y l (C H_{2} = C H -)$

Hence, Option "D" is the correct answer.

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