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Question

Arrange the following in increasing order of stability on the basis of resonance.
(i) CH2=CH−CH=CH−+CH2
(ii) CH2=CH−+CH−CH=CH2
(iii) CH2=CH−+CH−−CH−+CH2
(iv) +CH2−CH=CH−−CH−+CH2.

A
(ii) > (i) > (iii) > (iv)
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B
(iii) > (ii) > (i) > (iv)
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C
(i) > (iii) > (ii) > (iv)
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D
(iv) > (ii) > (iii) > (i)
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Solution

The correct option is B (ii) > (i) > (iii) > (iv)
(a) (ii)>(i)>(iii)>(iv)
(i) and (iii) should have greater stability as compared to (iii) and (iv) because of greater number of covalent bonds. Also (ii) has got 2o carbocation whereas (i) has 1o carbocation (iii) has unlike charges close to each other but (iv) has no such factor.

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