Arrange the following in order of decreasing acidic strength. nitrophenol (I), p-cresol (II), m-cresol phenol (IV) :

I > I V > I I > I I I

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I V > I I I > I I > I

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I > I I > I I I > I V

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I I I > I I > I > I V

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Solution

The correct option is B $I > I V > I I > I I I$
We know that +I $(- C H_{3})$ groups decrease acidity in Phenols while -I $(- N O_{2})$ groups increase them. Hence, $I$ is the most acidic while $I I I$ is the least (as +I group $- C H_{3}$ is situated closer to the $- O H$ group).
Hence, Option A is the correct answer.

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