Question

# Arrange the following in order of increasing reducing property.$$NaH$$, $$MgH_2$$ and $$H_2O$$

Solution

## $$NaH$$ is an ionic hydride and can easily donate its electrons. It is the most reducing. $$\displaystyle MgH_2$$ and $$\displaystyle H_2O$$ are covalent hydrides. $$\displaystyle H_2O$$ has lower reducing power than $$\displaystyle MgH_2$$ as it's bond dissociation energy is higher. Hence, the increasing order of the reducing property is $$\displaystyle H_2O < MgH_2 < NaH$$.ChemistryNCERTStandard XI

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