Question

Arrange the following in the order of increasing oxidation number of nitrogen: $N{H}_3,N_{3}H,N_{2}O,NO,N_2{O}_5$.

Answer 1

The order of increasing oxidation number of nitrogen: $N{H}_3,N_{3}H,N_{2}O,NO,N_2{O}_5$ is $N{H}_3(-3),N_{3}H(-1/3),N_{2}O(+1),NO(+2),N_2{O}_5(+5)$.
The numbers in bracket represents the oxidation number of nitrogen. With increase in the number of electronegative O atoms, the oxidation number of nitrogen increases.
The oxidation numbers of H and O are $+1$ and $-2$ respectively.