Arrange these haloalkanes in correct order of density:

C H_{3} I < C_{2} H_{5} I < C_{3} H_{7} I

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C H_{3} I > C_{2} H_{5} I > C_{3} H_{7} I

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C H_{3} I < C_{2} H_{5} I > C_{3} H_{7} I

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C H_{3} I > C_{2} H_{5} I < C_{3} H_{7} I

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Solution

The correct option is B $C H_{3} I < C_{2} H_{5} I < C_{3} H_{7} I$
Haloalkanes are more dense than alkane, from which they are derived and usually more dense than water. Density increases with the number of carbon and halogen atom increases.

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C H_{3} I

C_{2} H_{5} I

C_{2} H_{5} I

C_{2} H_{5} C l

C_{2} H_{5} B r

C_{2} H_{5} F

Consider the following haloalkanes:

$1. C H_{3} F 2. C H_{3} C l 3. C H_{3} B r 4. C H_{3} I$

The increasing order of reactivity in nucleophilic substitution reaction is:

C H_{3} I + x N a + C H_{3} I ⟶ C H_{y} C H_{y} + x N a I

C - X