As one considers orbits with higher values of n in a hydrogen atom, the electric potential energy of the atom

(a) decreases
(b) increases
(c) remains the same
(d) does not increase

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Solution

(b) increases

The electric potential energy of hydrogen atom with electron at the nth state is given by
$V = - \frac{2 \times 13.6}{n^{2}}$
As the value of n increases, the potential energy of the hydrogen atom also increases, i.e. the atom becomes less bound as n increases.

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As one considers orbits with higher values of n in a hydrogen atom, the electric potential energy of the atom (a) decreases (b) increases (c) remains the same (d) does not increase

(b) increases The electric potential energy of hydrogen atom with electron at the nth state is given by V=-2×13.6n2 As the value of n increases, the potential energy of the hydrogen atom also increases, i.e. the atom becomes less bound as n increases.

As one considers orbits with higher values of n in a hydrogen atom, the electric potential energy of the atom

(a) decreases
(b) increases
(c) remains the same
(d) does not increase

(b) increases

The electric potential energy of hydrogen atom with electron at the nth state is given by
$V = - \frac{2 \times 13.6}{n^{2}}$
As the value of n increases, the potential energy of the hydrogen atom also increases, i.e. the atom becomes less bound as n increases.