As per Hardy-Schulze formulation, the flocculation values of the following for ferric hydroxide sol are in the order:

A l C l_{3} > K_{3} [F e (C N)_{6}] > K_{2} C r O_{4} > K B r = K N O_{3}

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K_{3} [F e (C N)_{6}] < K_{2} C r O_{4} < A l C l_{3} < K B r < K N O_{3}

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K_{3} [F e (C N)_{6}] < K_{2} C r O_{4} < K B r = K N O_{3} = A l C l_{3}

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K_{3} [F e (C N)_{6}] > A l C l_{3} > K_{2} C r O_{4} > K B r > K N O_{3}

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Solution

The correct option is C $K_{3} [F e (C N)_{6}] < K_{2} C r O_{4} < K B r = K N O_{3} = A l C l_{3}$
The minimum concentration of an electrolyte which is required to cause the coagulation or flocculation of a sol is known as flocculation value. Flocculation value is inversely proportional to coagulation power (coagulation power is directly proportional to the valency of the ions causing coagulation). $F e (O H)_{3}$ sol is a positive sol and thus we have to consider the valency of the anions in the given electrolytes.

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