CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

As shown in the figure a ball of mass m hits a floor with a speed u=102 m/s making an angle of incidence α=45 with the normal. The coefficient of restitution is e=0.5. Find the speed of the reflected ball and the angle of the reflection.


  1. 102,tan1(1)
  2. 52,tan1(2)
  3. 55,tan1(2)
  4. 105,tan1(1)


Solution

The correct option is C 55,tan1(2)
Given, speed of ball before collision u=102 m/s
angle of incidence, α=45
e=0.5
As we know,
(e=VsepVapp) along line of impact.
Here,


(e=vucos45) along line of impact
 0.5×u×12=v
 vy=u22 along line of impact.
As we know,
Linear momentum of individual particles remains unchanged along perpendicular to common normal.
Hence, vx=usin45=u2 along common tangent.
Hence, we have
v=v2y+v2x= (u22)2+(u2)2
 v=5u22=5×10222=55 m/s
Angle of the reflection is given by,
tanβ=vxvy
 tanβ=⎜ ⎜ ⎜u2u22⎟ ⎟ ⎟=2
 tanβ=2
 β=tan1(2)

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
QuestionImage
QuestionImage
View More...


People also searched for
QuestionImage
QuestionImage
View More...



footer-image