Question

As the switch S is closed in the circuit shown in figure, current passed through it is

• A. Zero
• B. 1A
• C. 2A
• D. 1.6A

Answer 1

The correct option is C 2A


Let the potential at the point C be $V$.
By Kirchoff's current law:
$i_1+i_2=i_3\Rightarrow \frac{10-V}{4}+\frac{5-V}{2}=\frac{V-0}{2}\Rightarrow 10-V+10-2V=2V\Rightarrow 20=5V\Rightarrow V=4i_3=\frac{V}{2}=2A.$