Assertion (A) : $N a B O_{3} / O H^{-}$ can be used for oxidation of $C r^{3 +}$ to $C r^{6 +}$ .
Reason (R) : In alkaline solution $N a B O_{3}$ produces $H_{2} O_{2}$ .

(A) is correct; (R) is correct and (R) correctly explains (A).

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(A) is correct; (R) is correct and (R) doesn't explain (A) correctly.

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(A) is correct; (R) is incorrect.

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(A) is incorrect; (R) is correct.

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Solution

Sodium perborate undergoes hydrolysis in contact with water, producing hydrogen peroxide and borate. $H_{2} O_{2}$ oxidized $C r^{3 +}$ to $C r^{6 +}$ . Hence both the assertion (A) as well as the reason (R) are correct and (R) correctly explains (A).

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Similar questions

Assertion (A) : $N a B O_{3} / O H^{-}$ can be used for oxidation of $C r^{3 +}$ to $C r^{6 +}$ .
Reason (R) : In alkaline solution $N a B O_{3}$ produces $H_{2} O_{2}$ .

Q. Assertion (A):

A l (O H)_{3}

is amphoteric in nature.
Reason (R):

A l (O H)_{3}

H^{+}

donor acid as well as

O H^{-}

donor base.

Q. Assertion (A) :

B F_{3}

is a weaker Lewis acid than

B C l_{3}

.
Reason (R) :

B F_{3}

is is less electron-deficient than

B C l_{3}

In this question, an Assertion (A) is followed by a corresponding Reason (R). Choose the appropriate option.

Assertion (A): In $C s C l$ crystal, the coordination number of $C s^{\oplus}$ ion is 8.

Reason (R): $C l^{⊖}$ ions in $C s C l$ adopt bcc type of packing.

Q. Assertion:

C e^{4 +}

is used as an oxidizing agent in volumetric analysis.
Reason:

C e^{4 +}

has a tendency to attain its

+ 3

oxidation state.

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Assertion (A) : NaBO3/OH− can be used for oxidation of Cr3+ to Cr6+. Reason (R) : In alkaline solution NaBO3 produces H2O2.

Sodium perborate undergoes hydrolysis in contact with water, producing hydrogen peroxide and borate. H2O2 oxidized Cr3+ to Cr6+. Hence both the assertion (A) as well as the reason (R) are correct and (R) correctly explains (A).

Assertion (A) : $N a B O_{3} / O H^{-}$ can be used for oxidation of $C r^{3 +}$ to $C r^{6 +}$ .
Reason (R) : In alkaline solution $N a B O_{3}$ produces $H_{2} O_{2}$ .

Sodium perborate undergoes hydrolysis in contact with water, producing hydrogen peroxide and borate. $H_{2} O_{2}$ oxidized $C r^{3 +}$ to $C r^{6 +}$ . Hence both the assertion (A) as well as the reason (R) are correct and (R) correctly explains (A).