Assertion :In any △ABC the minimum value of r1+r2+r3r is 9 Reason: A.M≥G.M
A
Both Assertion and Reason are individually true and Reason is the correct explanation of Assertion.
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Both Assertion and Reason are individually correct but Reason is not the correct explanation of Assertion
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
Assertion is correct but Reason is incorrect
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Assertion is incorrect but Reason is correct
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B Both Assertion and Reason are individually correct but Reason is not the correct explanation of Assertion 1r1+1r2+1r3 =s−a△+s−b△+s−c△ =3s−(a+b+c)△ =3s−2s△ =s△=1r ∵ A.M≥ H.M ∴1r1+1r2+1r3≥3(1r1+1r2+1r3)=31r=3r or r1+r2+r3r≥9 ∴ Minimum value of r1+r2+r3r is 9