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Question

Assertion :When $$1.0$$ mol of $$NaCl$$ is doped with $$10^{-3}$$ mol $$SrCl_{2}$$, the number of cationic sites remaining vacant is $$10^{-3}$$. Reason: Each $$SrCl_{2}$$ unit produces two cationic vacancy.


A
Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
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B
Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
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C
Assertion is correct but Reason is incorrect
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D
Both Assertion and Reason are incorrect
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Solution

The correct option is C Assertion is correct but Reason is incorrect
One cation vacancy is produced by one $${Sr}^{2+}$$ because the charge neutralization is maintained. Hence, when $$1 mol $$ of $$NaCl$$ is doped with $${ 10 }^{ -3 } mol\ Sr{ Cl }_{ 2 }$$; the cationic sites remaining vacant is $${ 10 }^{ -3 }$$. 

Chemistry

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