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Question

Assume the following reaction is carried out in acidic medium. 
6e+Cr2O722Cr3++7H2O

How many H+ do we need to add to the LHS to balance the H atoms?



A

10

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B

6

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C

7

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D

14

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Solution

The correct option is D

14


Count number of Hydrogen on right hand side 7 ×2 = 14
Hence, add 14 H+ ions to the side which is deficient.
Cr2O72+6e+14H+2Cr3++7H2O


Chemistry

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