Question

# Assuming 200MeV of energy is released per fission of 92U235, calculate the energy released when 1kg of 92U235 undergoes complete fission. What percentage of mass of 92U235 gets converted into energy ?

A
5.126×1026MeV; 0.5 %
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B
5.126×1026MeV; 0.1 %
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C
4.126×1026MeV; 1.0 %
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D
8.126×1026MeV; 2.0 %
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Solution

## The correct option is B 5.126×1026MeV; 0.1 %235g of 92U235 contains Avogadro number (6.023×1023) of atoms.Number of atoms of 92U235 in 1kg of uranium =1000×6.023×1023235=2.563×1024Energy released = Number of atoms × energy released per fission. =2.563×1024×200MeV=5.126×1026MeVThe mass that liberates the above energy can be calculated using E=mc2 ......(2)where E=5.126×1026×1.6×10−13J=8.2×1013Jc=3×108ms−1Substituting in (2), we get m=Ec2=8.2×10139×1016=9.11×10−4kg% of mass =9.11×10−41×100=0.0911% =0.1 % approximately.

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