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Question

Assuming that Hund’s rule is violated, the bond order and magnetic nature of the diatomic molecule B2 is :


A
1 and diamagnetic
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B

0 and diamagnetic

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C

1 and paramagnetic

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D

0 and paramagnetic

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Solution

The correct option is A 1 and diamagnetic
As Hund’s rule is violated, molecular orbital configuration of B2 would be :
σ1s2 > σ1s2 > σ2s2 > σ2s2 > π2py2 = π2px0

Since all the electrons are paired, hence B2 is diamagnetic.

Bond order of B2=NbNa2
Bond order of B2=642=1

Hence, option (a) is correct.

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