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Question

At 100C and 1 atm, if the density of liquid water is 1.0 g/cm3 and that of water vapour is 0.0006 g/m3 , then the volume occupied by water molecules in 1 litre of steam at that temperature is
  1. 6cm3
  2. 60cm3
  3. 0.6cm3
  4. 0.06cm3


Solution

The correct option is C 0.6cm3

Mass of water vapor = density x Volume = 0.0006 g/cm3 x 1 litre = 0.0006 g/cm3 x 103 cm3 
Mass of water vapor = 0.6 g
Volume occupied by water molecules of vapor 
= volume of same amount of water in liquid phase 
= mdensity of water=0.6g1g cm3 = 0.6 cm3 

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