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Question

At 143 K, the reaction of XeF4 with O2F2 produces a xenon compound Y. The total number of lone pair(s) of electrons present in 1 molecule of Y is:

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Solution

The complete reaction is:
XeF4+O2F2XeF6+O2

In XeF6 each F atom contains 3 lone pairs and the central atom Xe contains one lone pair. Thus, the total number of lone pairs = 6×3+1=19

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