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Nernst Equation

At 18oC, th...

Question

At $18^{o} C$ , the mobilities of $N H {_{4}}^{+}$ and $C l O {_{4}}^{-}$ ions are $6.6 \times 10^{- 4}$ and $5.7 \times 10^{- 4} c m^{2} v o l t^{- 1} s e c^{- 1}$ respectively, at infinite dilution.
The equivalent conductance of ammonium chlorate solution is :(in $m h o c m^{2}$ )

A

118.67

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B

34.26

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C

49.14

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D

57.26

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Solution

The correct option is A $118.67$
According to Kohlrausch's law, Standard conductance of $N H_{4} C l O_{4} = λ_{(C l O_{4}^{-})}^{0} + λ_{(N H_{4}^{+})}^{0}$
$λ = F \times U$ , where $F = 96, 500 C$ and $U =$ ionic mobility
Standard conductance $(N H_{4} C l O_{4}) = F U_{(C l O_{4}^{-})}^{0} + F U_{(N H_{4} +)}^{0}$
Standard conductance $(N H_{4} C l O_{4}) = 96500 (6.6 \times 10^{- 4} + 5.7 \times 10^{- 4})$
$= 118.67$ $m h o c m^{2}$

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Similar questions

18^{\circ} C

, the mobilities of

N H_{4}^{+}

C l O_{4}

^{-}

6.6 \times 10^{- 4}

5.7 \times 10^{- 4} c m^{2} v o l t^{- 1} s e c^{- 1}

at infinite dilution. Calculate the equivalent conductance of ammonium chlorate solution.

18^{\circ} C

the mobilities of

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6.6 \times 10^{- 4}

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