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Question

At 27 C, 8 g of helium occupies a volume V. The gas expands adiabatically to 8V, then the work done by gas during expansion is approximately equal to
  1. 5610 J
  2. 6125 J
  3. 3785 J
  4. 4385 J


Solution

The correct option is A 5610 J
TVγ1=Const    300.Vγ1=T.(8V)γ1300.Vγ1=T 8γ1.Vγ1T=3008γ1   [γ=CpCV=53]=30082/3=3004=75 KW=nRγ1[ΔT]=2×8.312/3(225)=/2×8.31×3/2×225=25×225W=5610 J 

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